Showing posts with label SOLUTION IN 91 TO 100.. Show all posts
Showing posts with label SOLUTION IN 91 TO 100.. Show all posts

Thursday, 12 February 2015

SOLUTION IN 91 TO 100.

 91.   Required digit = Unit digit in (4x 8x 7x 3) = 2.

92.   Required digit =  unit digit in ( 1x 2x 3x 4x 5x 6x 7x 8 x  9) = 0.

93.   (9 x 6 x 4 )= 216. In order to obtain 2at the unit place, we must multiply 216 by 2 or 7.

  Of the given numbers, we have7.

94.   Unit digit in (3127)¹⁷³ = unit digit in (7) ¹⁷³.now 7⁴ gives unit digit 1.
(7)¹⁷³ = (7⁴)⁴³ x 7¹.thus, (7)¹⁷³, gives unit digit 7. 

95.    Unit digit in 7⁴ is 1.
Unit digit in 7⁶⁸ is 1.
Unit digit in 7⁷¹ is 3.
Again, every power of 6 will give unit digit 6.
Unit digit in 6⁵⁹ is 6.
Unit digit in 3⁴ is 1.
Unit digit in 3⁶⁴ is 1. Unit digit in 3⁶⁵ is 3.
Unit digit in(⁷¹ x 6⁵⁹ x 3⁶⁵) = unit digit in (3 x 6 x 3) = 4.

96.   Unit digit in 7⁴ is 1. So, unit digit in 7⁹² is 1.
Unit digit in 7⁹⁵ is 3.
Unit digit in 3⁴ is 1.
Unit digit in 3⁵⁶ is 1.
Unit digit in3⁵⁸is 9.
Unit digit in (7⁹⁵ - 3⁵⁸) = (13 – 9) = 4.

97.   X⁴ᶮ = (2⁴)ᶮ or (4⁴)ᶮ or (6⁴)ᶮ or (8⁴)n/
Clearly, the unit digit in each case is 6.

98.   (3x 5)¹² x (2 x 7)¹⁰ x (10)²⁵ = (3x 5)¹² x (2x 7)¹⁰ x (2 x 5)²⁵
             = 3¹² x 5¹² x 2¹⁰ x 7¹⁰x 2²⁵ x 5²⁵ = 2³⁵ x 3¹² x 5³⁷ x 7¹⁰.
Total number of prime factors = (35 + 12 + 37 + 10) = 94.

99.   Given exp. = a² + b² + 2ab , where a =397 and b= 104.
  = (a + b)²= (397 + 104)² = (500 + 1)² =(500)² + 1² + 2 x 500 x1
= (250000 + 1 + 1000 = 251001. ²

100.        Given exp. = = a² + b² + 2ab, where a  =186 and b=  159

 = (a + b)²=(186 -159)² = (27)²
=(20 + 7)² = (20)²+ 7² + 2 x 20 x 7 =400 + 49 + 280 = 729.

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