Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 121 130). Show all posts
Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 121 130). Show all posts

Sunday, 15 March 2015

EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 121 130)

121.       3X – 5y = 5 ….(I) and x/  y  =5/7   7X= 5X = 5y  2X = 5y =0 .. (II)

Subtracting (II) from (I), we get: X =5.

Putting X =5 in (I), we get: y =2. So, x –y = 5 -2 =3.

122.       4 X + 3y = 18xy …(I) and 2 x -5y=  - 4xy

Dividing (I) and (II) by X y, we get: 3/X + 4/y = 18…..(III) and 5/X – 2/y = 4…(iv)

Multiplying (iv) by 2 and adding (III) to it, we get: 13/x = 26 or x = 1/2.

Putting X = ½ in (III), we get: y = 1/3.

123.       2X + y =17 …(I); Y + 2z =15 …(II) and x + y =9

Subtracting (III) from (I), we get: X =8.

Putting X =8 in (I), we get: y = 1. Putting =1 in (II-, we get: 2z =14 or z=7.

4  X + 3y X z = 4 x 8 + 3 x 1 + 7 = 42.

124.       3 X – 4y + z =7 .. (I) ;  2 X + 3y – z =  19…. (II) and x + 2y +2z = 24…..  (III)

Adding (I), (II), we get: 5x –y =26

Subtracting (I) from (II) and adding to (III), we get: 9y =36 or y =4.

Putting y =4 in (iv), we get: 5X – y =26.

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