161. Suppose
snaked earns Rs. X in each of the other eleven months.
Then,
sanket’s earning in March = Rs. (2X)
Sanket’s
annual earning =Rs. (11 x + 2X) = Rs. (13X).
Required fraction
= 2x/ 13x = 1/13.
162. Let
the capacity of the tank be X litres, then, 1/3x = 80 X = 240
1/2 X
= 120.
163. Distance
travelled on foot = [7/2 – (5/3 + 7/6)] km = (7/2 – 17/6) km = 2/3 km.
Required
fraction = (2/3) / (7/2) = (2/3 +2/7) = 4/ 21.
164. Let
the required fraction be X. then,
4/7 X
+ 4/7 = 15/14 4/7X (15/14 – 4/7 ) =
7/14 = ½ X = (1/2 x 7/4 ) = 7/8.
165. Required
fraction 2/3 of ¼ of Rs. 25. 10 / 3/2 of Rs. 36 = Rs.4.20 /Rs. 54 = 42 /540 = 7/ 90.
= 7/90
166. Let
the length of longer piece be X cm. the, length of shorter piece =(2/X)cm
X +
2/5X = 70 7X / 5 = 70 X = (70 x 5 / 7) = 50.
Hence,
length of shorter piece = 2/5X = (2/5x 50) cm = 20cm.
