Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 101 110). Show all posts
Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 101 110). Show all posts

Sunday, 15 March 2015

EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 101 110)

101.       6 a + 4 b /6 a – 5 b  = 6 ( a/ b) + 4 / 6 ( a / b – 5 = 6 x 4/3 + 4/ 6 x 4/3 – 5 = 8 + 4 8-5 = 12/3 = 4.

102.       X/2y = 6/7  X/y = (2 x 6/7 ) = 12/7.

X – y / X + y +X / y – 1 / X/y + 1 + 14 /19 = 12/7 -1 / 12 / 7 + 1 + 14 / 19 = (5/7) / 

(19.7) + 14/19

= (5/7 x 7/19 ) + 14/19 = 5/19 + 14/19  = 19/19 = 1.

103.       1/b = 4/5 and b/c = 15/16 = ( a/b x b/c ) = (4 / 5 x 15/16)  a /c = 3/4

 c² - a²/c² + a² = 1 – (a/c)²/ 1+ (a²/ c²) = 1 – (a/c)²/1 + (a/c)² = 1 – 9/16 / 1 + 9 /16 = (7 

/16) / (25 /16) = 7 / 25

= 7/25.
104.       (a – c ) – (b + d ) = 6 and (c –d ) ( a + b ) =3

( a – c) – (b + d) = 6 and (c –a) –( b + d) =3

(b + d) = (a –c) -6 and (b + d) = (c – a) -3

( a –c ) = -6 = (c –a) -3

2 (a –c) =3

( a-c) = 3/2 =1.5

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