Showing posts with label EXERCISE 2 SOLUTIONS: IN 1 TO 10:. Show all posts
Showing posts with label EXERCISE 2 SOLUTIONS: IN 1 TO 10:. Show all posts

Friday, 20 February 2015

EXERCISE 2 SOLUTIONS: IN 1 TO 10:

                                         
1.       Clearly, 252 = 2 x 2 x 3 x 3 7.

2.       99 = 1 x 3 x 3 x 11; 101 = 1 x 101;

176= 1 x 2 x 2 x 2 x 2 x 11; 182 = 1 x 2 x 7 13.

  So, divisors of 99 are 1, 3, 9, 33 and 99;
  Divisors of 101 are 1 and 101;
  Divisors of 176 are 1, 2, 4, 8, 16, 22, 44, 88 and 176;
  Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182,
  Hence, 176 has the most number of divisors.

 3.       N                       divisors excluding n                          sum of divisors
        6                                 1, 2, 3                                               6
        9                                 1, 3                                                   4
      15                                 1, 3, 5                                                9
      21                                 1, 3, 7                                               11
Clearly, 6 is a perfect number

4.      H.C.F. = product of lowest powers of common factors = 2² x 3² x 5

5.       H.C.F. = product of lowest powers of common factors =- 3 x 5 x 7 =105

6.       4 x 27 x 3125 = 2² x 3³x 5; 8 x 9 x 25 x 7 =2³ x 3² x 5² x 7;

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