Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 181 190). Show all posts
Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 181 190). Show all posts

Monday, 16 March 2015

EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 181 190)

181.       Let the capacity of 1 bucket =X. then, capacity of tank = 25X.

     New capacity of bucket = 2/5 X.

      Required number of buckets = 25X/ (2X \ 5) = (25 X x 5/2X) = 125/2 = 62 1/2.

182.       Suppose initially peter had Rs .X. then,

     Amount received by Michael = Rs. (x/4).

     Amount remaining with peter = Rs. ( x – x/4) = Rs. (3x/4).

     Amount received by Sam = Rs. (1/2 x x/4) =Rs. (x/8).

     3X/ 4 – X/8 = 500    %x = 4000    X = 800.

183.       A’s share = 1/3. Remainder = (1 -1/3) =2/3.

      B’s share = 2/5 of 2/3 = 4/15. Rest = (2/3 -4/15 ) = 6/15 = 2/5.

      C’s share =D’s share = ½ of 2/5 = 1/5.

184.       Part read on first day = 3/8.remaining part = (1 -3/8) = 5/8.

     Part read on second day = 4/5 of 5/8 = ½. Unread part = [1 – (3/8 + 1/2)] = 1/8.

     Let the number of pages be X. then, 1/8 x = 30 or x =30 x 8 = 240.

185.       Wife’s share = 1/2 .remaining part = (1 -1/2) =1/2.

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