Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 141 150). Show all posts
Showing posts with label EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 141 150). Show all posts

Monday, 16 March 2015

EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 141 150)

141.       Original number of sections = (16 – 3) =13.

      Original number of students =( 24 x 16 ) =312

      Present number of students = (21 x 16) = 336.

     Number of new students admitted = (336 – 312) = 24.

142.       Time between 10 a.m. and 13. 27 hours = 3 hrs. 27 min. = 207 min.

               For three periods in between free time = 15 min.

               Remaining time = (207 – 15) min. = 192 min.

               Duration of each of the 4 periods = (192 / 4 ) min. = 48 min.

143.                                Hrs.        Min.      sec

               3               17         49

                              (-)  1                54         50

                                1                  22        59

                        
                              Total time = (1 x 60 + 22) min.  + 59 sec. = (82 x 60 + 59) sec. = 4979 sec.

                                Number of times the light is seen = (4979 / 13 + 1) = 384.

144.       Money earned in 2 days = Rs. (20 – 15) = Rs. 5.

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