H.C.F. AND L.C.M. OF NUMBERS (EXERCISE 2 SOLUTIONS 451 TO 60:)

51. Required number of students = H.C.F. of 1001 and 910 = 91 

52. Largest size of the tile = H.C.F. of 378 cm and 525 cm = 21 cm.

53. REQUIRED NUMBER = H.C.F.  Of (91 – 43), (183 – 91) and (183 – 43)

                                         = H.C.F. of 48, 92 and 140 = 4

54. N = H.C.F. of (4665 – 1305), (6905 – 4665) and (6905 – 1305)

     = H.C.F of 3360, 2240 and 5600 = 1120.

      Sum of digits in N= (1+ 1 + 2 + 0) = 4.

55.  Required number = H.C.F of (1356 – 12), (1868 – 12) and (2764 -12)

                                   H.C.F. of 1344, 1856 and 2752 = 64.

56. Required number = H.C.F. of (1657 – 6) and (2037 – 5)

                                  H.C.F. of 1651 and 2032 =127.

57. L.C.M. of 8, 16, 40 and 80 = 80.

       8/8 = 70/80; 13/16 = 65/80; 31/40 = 62/80.

       Since, 70/80 > 63/80> 65/80 > so 7/8 > 63/80 > 13/16> 31/40.

       So, 7/8 is the largest.

58. L.C.M.  of 12, 18, 21, 30