Showing posts with label NUMBERS.. Show all posts
Showing posts with label NUMBERS.. Show all posts

Monday, 9 March 2015

EXERCISE 4 (OBJECTIVE TYPE QUESTIONS in 101 110)

101.       If 2a + b / a + 4b =3, then find the value of a + b / a+ 2b.

a)      2/7

b)      5/9

c)       10/7

d)      10/9


102.       if (2a + 3b) 2c – 3d) =(2c – 3b) (2c + 3d), then:


a)      1/b = c/d

b)      A /d = c/d

c)       a/n d/c

d)      n/a = c/d

103.       a) If (2a + 3b) (2c – 3d) (a – b – 2c + 3d) =a – b + 2c – 3d) ( a+ b -2c – 3d), then 2 b c is equal to:

a)      3/2

b)      3a/2d

c)       3ad

d)      a²d²

104.       if X =1 – Q and Y = 2q +1, then for what value of q, x is equal toy?

a)      -1

b)      0

c)       1/2

d)      2

105.       Find X if x/5 – X/6 =4.

a)      -120

b)      -100

c)       100

d)      120

106.       If 4 X =5Y =83 and 3X /2y = 21/22, then Y-X =?

a)      3

b)      4

c)       7

d)      11

107.       Which of the following values of X and Y satisfy the following equations I and II?

I.                    3 X + Y = 190   

II.                  X – Y = 9

a)      -7, -2

b)      -7,2

c)       7,-2

d)      7,2

108.       If a +b =5 and 3a + 2b =20, then (3a +b_ will be;

a)      10

b)      15

c)       20

d)      25

109.       If 2p +3q = 18 and 2p – q=2, then 2p + q =?

a)      6

b)      7

c)       10

d)      20

110.   If  2X + y =5 and 3X – 4y -2,then the value of 2xy is:

a)      4

b)      6

c)       8

d)      10

ANSWERS

EXERCISE 4 (OBJECTIVE TYPE QUESTIONS in 41 50)

41.       Supply the two missing figures in order indicated by x and in the given equation, the fractions being in their lowest terms.

5 1/ X x Y 3/4 = 20.

a)      3, 1

b)      3,3

c)       4,1

d)      5,3

42.       The difference of 1 3/16 and its reciprocal is equal to:

a)      1 1/8

b)      4/3

c)       15/16

d)      None of these.

43.       How many 1/8s are there in 37 ½?

a)      300

b)      400

c)       500

d)      Cannot be determined.

44.       3/8 is what part of 1/12?

a)      3/7

b)      1/12

c)       4/3

d)      None of these

45.       The smallest fraction which should be subtracted from the sum of 1 ¾, 21/2,5 7 /12 3 ½ and 2 ¼ to make the result a whole number is:

a)      5/12

b)      7/12

c)       1/2

d)      7

46.       If X is a positive number, then which of the following fractions has the greatest values?

a)      X/X

b)      X/ X+1

c)       X+1/X

d)      X + 2/X + 3

47.       By how much is three – fifth of 350 greater than four – seventh of 210?

a)      95

b)      110

c)       120

d)      210

e)      None of these

48.       By how much does 6/7/8 exceed 6/7/8?

a)      6 1/8

b)      6 3/4

c)       7 3/4

d)      7 5/6

49.       If 4/5 of an estate be worth Rs. 16,800, then the value 3/7 of the estate is:

a)      Rs. 9000

b)      Rs. 21,000

c)       Rs. 72,000

d)      Rs. 90. 90,000

50.   Two – fifth of none – fourth of three – Seventh of a number is 15. What is half of that number?

a)      94

b)      96

c)       188

d)      196


e)      None of these 

ANSWERS 

Sunday, 15 February 2015

SOLUTION IN 141 TO 150

141   Let the required number be X.
       Then, (11 X + 11) = 11 ( X + 1) is divisible by 13, so, X =12

14     Let the 3-digit number be X y z . then,
      ( 100 X + 10 y + z) – (X + y + z) = 99 X + 9 y = 9 (22 X + y), which is divisible by 9.

143.     Putting X =5 and y + 1, we get (3 X + 7 y) = ( 3 x 5 + 7 x 1 ) = 22, which is divisible           by 11.

4 x + 5 y = (4 x 5 x 5 x 1 ) = 25, which is not divisible by 11.
X + y + = (5 + 1 + 4) = 9, which is not divisible by 11.
9 x + 4 y (9 x 5 x 4 x 1 ) = 49, which is not divisible by 11..
4 X – 9 y = (4 x 5 – 9 x 1) = 11, which is divisible by 11.


144.                   4 a 3
                 9  8  4                                       a + 8 = b     b- a + 8
                 13 b 7

 
Also, 13 b 7 is divisible by 11.
 (7 + 3) – ( b + 1 )  = ( 9 =b) ( 9 –b) = 0  b= 9.
B = 9 and a = 1 (a+ b) =10.


145.                  Required number = (2⁵ - 2 ) =(32 – 2) 30.

146.                  Required number = product of first three multiples of 3 = (3 x 6 x 9 ) = 162
.
147.                  On dividing 1000 by 45, we get remainder = 10.
                Required number to be added = ( 45 – 10) = 35.

148.                  On dividing 803642 y 11, we get remainder = 70.
                Required number to be added = (11 – 4 ) = 7.

149.                  On dividing 6709 by 9, we get remainder = 4.
                Required number to be subtracted = 4.

150.                  On dividing 427398 by 15, we get remainder = 3.
                Required number to be subtracted = 3.

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