161. Suppose
snaked earns Rs. X in each of the other eleven months.
Then,
sanket’s earning in March = Rs. (2X)
Sanket’s
annual earning =Rs. (11 x + 2X) = Rs. (13X).
Required fraction
= 2x/ 13x = 1/13.
162. Let
the capacity of the tank be X litres, then, 1/3x = 80 X = 240
1/2 X
= 120.
163. Distance
travelled on foot = [7/2 – (5/3 + 7/6)] km = (7/2 – 17/6) km = 2/3 km.
Required
fraction = (2/3) / (7/2) = (2/3 +2/7) = 4/ 21.
164. Let
the required fraction be X. then,
4/7 X
+ 4/7 = 15/14 4/7X (15/14 – 4/7 ) =
7/14 = ½ X = (1/2 x 7/4 ) = 7/8.
165. Required
fraction 2/3 of ¼ of Rs. 25. 10 / 3/2 of Rs. 36 = Rs.4.20 /Rs. 54 = 42 /540 = 7/ 90.
= 7/90
166. Let
the length of longer piece be X cm. the, length of shorter piece =(2/X)cm
X +
2/5X = 70 7X / 5 = 70 X = (70 x 5 / 7) = 50.
Hence,
length of shorter piece = 2/5X = (2/5x 50) cm = 20cm.
167. Let
the whole amount be Rs. X the, A’s share = Rs. (3 /16X); B’s share = Rs. (X/4);
and C’s share = Rs. [X – (3X / 16 + X /4 )] = Rs. (9X /16).
9x / 16 = 81 X = (81 x 16 / 9) = 144.
Hence, B’s share = Rs.(144/4 ) = Rs. 36.
168. Green
portion = [ 1 – (1 /10 + 1/20 + 1/30 + 1/40 + 1/50 + 1/60)]
= [1 – 1/10 ( 1 + ½ + 1/3 + ¼ + 1/5 + 1/6 ) ] = 1
– 1/10 x 147 / 60 = 1 - 147 / 600 = 453
/ 600.
Let the length of the pole be X metres.
The, 453 / 600 X = 12.08 x = (12.08 x 600 /453) = 16.
169. Let
the number be X. then,
3/4 X – 3/14
X = 150 21X -6 X = 150 x 28 15X = 150 x 28 X = 280.
X = 280
170. Let
the sum be Rs. X. then,
8/3 X –
3/8X = 55 64X – 9X = 55 x 24 X = (55x 24 /55 ) = 24.
Correct answer
= Rs. (3/8 x 24) = Rs. 9.
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