171. Let
the fraction be a/b = 512 /27
a / b x a/b x a/b =512 /27
(a/b)
³
= (8/3)³ a/b = 8/3 = 2 2/c.
172. Maximum
internal assessment score = (47 / 50 x 10) = 9. 4.
Minimum internal assessment score = (14/50 x
10) =2.8.
Required
difference = (9.4 – 2.8) = 6.6.
173. Let
savings in N.S.C and P.P.F. . be Rs. x and Rs. (150000 – x ) respectively. Then,
1/3 X = 1/2 (15000000 –X) x/3 + X/2 =
75000 5x/6 = 75000 X = (75000 x 6/5) = 90000.
Savings in public provident fund = Rs. (150000
– 90000) = Rs. 60000.
174. Let
there be (X + 1) members. The,
Father’s
share =1/4, share of each other members = 3/4X.
3
(3/4X) = ¼ 4X = 36 X = 9.
175. Let
salary =Rs. X. then, tips = Rs. (5/4 X).
Total income = Rs. (x + 5/4 X) =
Rs. (9X / 4).
Required fraction = (5X / 4 x 4 / 9X ) = 5/9.
176. Let
C’s share = Rs. X. then, B’s share = Rs. (x/4), A’s share = Rs. (2/3 x x/4)
=Rs. X/6.
X/6 +
X/4 + X = 1360 17X / 12 = 1360 X = (1360 x 12 / 17) =Rs. 960.
Hence,
B’s share = Rs. (960/4) = Rs. 240.
177. Let
Tanya’s share = Rs. X. then, Veena’s share = Rs. (x/2)
Amita’s
share = Rs. (2/3 x X/2) = Rs. (X/3). Total bill = Rs. (X+ X/2 + X/3) =
Rs.
(11X/6).
Required
fraction = (X / 2) x 6 /11x) = 3/11.
178. Let
the capacity of the tank be X litres. Then, ¼ X = 135 X = 135 x 4 = 540.
Required
fraction = (180 / 540) = 1/3.
179. Let
the capacity of the tank be X litres.
Then,
6/7X – 2/5X = 16 30X – 14X = 16 x
35 16X = 560 X = 35.
180. Let
the capacity of the bucket be X litres. Then,
Capacity
of 1 large bottle = X/4; capacity of 1 small bottle = X/7.
Fluid left in large bottle = ( x/4 – X/7) =
3X/ 28
Required fraction = (3X / 28 / X 4) = (3X
/ 28 x 4/X) = 3/7.
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