EXERCISE 4 (OBJECTIVE TYPE QUESTIONS SOLUTION IN 91 100)

91.       Given exp. = 4.59 /36 + 0.6 – 0.2 = 4.59 /2 + 0.6 = 2.295 + 0.6 – 0.2 = 2.695

92.       Let 64.4 – 34.7125/6.25 of X =1. Then, 6.25 of X = 29.6875.

X =29.6875/6.2 = 2968.75 /625 = 4.75 = 4.75 = 4 3/4

93.       Given exp. = 2.002 + 7.9 { 2.8 – 6.3 x 2.1 + 15.6}

= 2.002 + 7.9 {2.8 -13.23 + 13.23 + 15.6 } = 2.—2 + 7.9 x 5.17

= 2.002 + 40.843 = 42.845.

94.       Let 24 – [2.4 – {.24 –{24 x 2 – (.024 –X)}] = 22.0584.

Then, 24 – [2.4 –(.48 -.024 +X}] = 22.0584 – 22.0584  

24 – 1.944 + X = 22. 0584

X = 2.0584 – 22.056 = 0.0024.

95.       Let 3 –[1.6 –{ 3.2 + 2.25/X)}]= 0. 65.

Then, 3 – [ 1.6 –{3.2 – 3.2 – 2.25/X }] = 0.65

3-[ 1.6 + 2.25 /X  ] = 0.65

3 – 1.6 – 2.25/X =0.65

2.25/X = 1.4 – 0.65

X = 2.25 / 0.75 = 3.

96.       Let 587.4  + 58. 74 x 2 - 5. 874 /X = 702. 744.

Then, 5. 874/ X = 587.4 + 117.48 – 702. 744 = 2.136

X= 5. 874 / 2.136 = 5874/2136 = 11/4 = 2  3/4

97.       Let 54. 27 – [12. 84 – { X – (6.82 – 1.85)}] = 38.33.

Then, 54.27 – [12.84-{ X – 4.97}0] = 38.33.

Then, 54. 27 – [12. 84 – {x – 4. 97}] = 38. 33.

54.27 – [ 12. 84 – X +4. 97}] = 38.33

54.27 – [ 17. 81 – X ] = 38.33

54.27 – 1781 + X = 38.33

X = 38.33- 36 = 1. 87.

98.       Let 20/3 of 726/100 ÷ 45/100 of X = 968/117.

Then, 242/ 5  ÷  45/ 100 of X = 968/1117.

X = 242 /5 X 100 /45 x 117/ 968 = 13.

99.       P + Q  / P – Q = P/ Q + 1 / P /Q – 1 =7 + 1 /7 -1  = 8 / 6 = 4/3.

100.   (4/7 + 2y =X / 2y + X ) = ( 4/7 + 2 – X / Y   ?  2 +  X / y )  = 4/7 + 2 – 4/5  / 2 + 4/5 = 

4/7 + ( 6/5 x 6/14)  = 4/7 + 3/7 = 7/7=1.