EXERCISE 7A (OBJECTIVE TYPE QUESTIONS IN 36 40 SOLUTION )

36.       The difference between two integers is 5. Their product is 500. Find the numbers.

a)      15,20

b)      20,25

c)       30,25

d)      21,26

37.       Two numbers differ by 5. If their product is 336, then the sum of the two numbers is

a)      21

b)      28

c)       37

d)      51

38.       Two different natural numbers are such that their product less than their sum . One of the numbers must be:

a)      1

b)      2

c)       3

d)      None of these

39.       The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is :

a)      380

b)      395

c)       400

d)      425

40.       The difference between two numbers is 1365. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is:

a)      240

b)      270

c)       295

d)      360

ANSWERS 

36.B

37.C

38.A

39.C

40.B

SOLUTION 

36.       Let the integers be X and (X + 5). Then,

X (x +5) = 500 X² + 5X – 500 = 0   (x + 25) (x – 20) = 0  X = 20.

So, the numbers are 20 and 25.

37.       Let the numbers be X and Y. Then, x – y= 5 and xy = 336.

(X +y)² = (X – Y ) + 4xy = 25 + 4 x 336 = 1369   x + y =1369 = 37.

38.       Since 1. X < 1 + x, so one of the numbers is 1.

39.       Lt the numbers be X and y. then, xy = 9375 and X/ y = 15.

Xy / ( x/ y) = 9375 / 15    y² = 625  Y = 25       x = 15y  = 25   x = 15y   = (15 x 25 ) = 

375.

Sum of the numbers = 375 + 25 = 400

40.       Let the numbers be x and (X + 1365).

Then, X + 1365 = 6X + 15    5X = 1350 X = 270.