Tuesday, 10 February 2015

EXERCISE MARK AGAINST THE CORRECT ANSWER IN EACH OF THE FOLLOWING: IN 131 TO 140:

130.(51 + 52 + 53 + ….   +100) =?
a)      2525
b)      2975
c)       3225
d)      3775
131.(1 – 1/n) + ( 1 – 2/n) + (1 – 3/n) + …. Up to n terms =?
a)      1/2n
b)      ½ (n-1)
c)       ½ n(n-1)
d)      None of these
132.How many natural numbers are there between 23 and 100 which are exactly divisible by 6?
a)      8
b)      11
c)       12
d)      13
e)      None of these
133.The sum of all two  digit numbers divisible by 5 is
a)      1035
b)      1245
c)        1230
d)      945
e)      None o f these
134.The sum of how many terms of the series s 6+ 12 +18 +  24 …. Is 1800?
a)      16
b)      24
c)       20
d)      18
e)      2
135.How many terms are there in the G.P. 3, 6, 12 24, 384?
a)      8
b)      9
c)       10
d)      11
e)      7
136.2 +2 ²+ 2³ + ….2⁹ =?
a)      2044
b)      1022
c)       1056
d)      None of these
137.(1² + 2² + 3² + ….+ 10²) =?
a)      330
b)      345
c)       365
d)      385
138.(2²+ 4²+ 6²+ ….+ 20²)=?
a)      770
b)      1155
c)       1540
d)      385 x 385
139.(11² +12² + 13²+ …..+ 20²) =?
a)      385
b)      2485
c)       2870
d)      3255
                       ANSWERS

131.(D)
132.(B)
 133.(D)
 134.(D) 
135.(B) 
136.(A) 
137.(B) 
138.(D) 
139.(C) 
140.(B).

       

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