Thursday, 26 February 2015

DECIMAL FRACTIONS- EXERCISE 3 (OBJECTIVE TYPE QUESTIONS 106 TO 110)

 106.   The simplification of 0.2 x 0.2 + x 0.02 – 0.4 x 0.02 / 0.36 gives:

a)      0.009

b)      0.09

c)       0.9

d)      9

107.   The expression 11.98 x 11.98 + 0.02 x 0.02)will be a perfect square for X equal to:

a)      0.02

b)      0.2

c)       0.04

d)      0.4

108.   The value of (2.697 – 0.498)² + (2.697 + 0.498)²/2.697 x 2.697 + 0.498 x 0.498 is:

a)      0.5

b)      2

c)       2.199

d)      3.195

109.   The value of (0.137 + 0.098)² +(2.697 + 0.498)²/0.137 x 0.098 is:

a)      0.039

b)      0.235

c)       0.25

d)      4

110.   The value of (0.051 x 0.051 x 0.051 + 0.041 x 0.041 x 0.041)/0.051 x0.051 – 0.051 x 0.041 +0.041 x.047) is:

a)      0.00092

b)      0.0092

c)       0.092

d)      0.92
ANSWERS:

106.
1078.
108.
109.
110.


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