Friday, 20 February 2015

EXERCISE 2 SOLUTIONS: IN 11 TO 20

  11. H.C.F. of 148 and 185 is 37.
                L.C.M. = (148 x 185/37) = 740.

   12. Required H.C.F = H.C.F. of 2, 8, 64, 10 = 2
                                   L.C.M. of 3, 9, 81, 27= 81

1      13. Required H.C.F. =                 H.C.F. of 9, 12, 18, 21  = 3
                                               L.C.M. of 10, 25, 35, 40= 2800

 14. Required L.C.M. =                L.C.M. of 1, 5, 2, 4 = 20
                                                   H.C.F. of 3, 6, 9, 27   = 3

                     15. Required L.C.M =              L.C.M of 2, 3, 4, 9    = 36           =36.
                                                H.C.F. of 3, 5, 7, 13     = 1

16. Given numbers with two decimal places are: 1, 75, 5, 60 and 7.00. Without decimal places,          this number s are: 175,560 and 700, whose HC.F. Is 35.
    H.C.F.  of given numbers = 0.035.

 17.     H.C.F of given numbers = 0.18

  Given numbers are 1.08, 0.36 and 0.90. H.C.F. of 108 and 720 is 18.

18. Given numbers are 0. 54, 1.80 and 7. 20. H.C.F. of 54, 180 and 720 is 18.
      H.C.F. of given numbers = 0.18

19. Given numbers are 3.00, 2.70 and 0.09. L.C.M. of 300, 270 and 9 is 2700.
      L.C.M. of given numbers = 27.00 = 27.

20. 3240 = 2² x 3⁴ x 5; 3600 = 2⁴ x 3² x 5²; H.C.F. = 36 = 2² x 3²
Since H.C.F. is the product of lowest powers of common prime factors, so the third number must have 3⁵ and 7² as its factors.
Third number = 2² x 3⁵ x 7². 

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