DECIMAL- FRACTIONS - EXERCISE 3 (SOLUTION 41 TO 50)

41.      0.213/0.00213 = 0.213 x 100000/0.00213 x 100000 = 213 x 100/213 = 100.

42.       4.036/0.04 = 403.6/4 =100.9

43.      1/0.04 = 100/4 = 25

44.      (0.05/0.25+ 0.25/0.05)³ = (5/25 + 25/5)³= (1/5 + 5)³ = (26/5)³ = (5.2)³ = 140.608.

45.      0.0396/2.51 = 3.96/251 = (396/251 x 100) = 1.577/100 = 0.01577 = 0.016.

46.      Let .04 x X = .000016. Then, X =.000016/.04 = 0.01577 = 0.016.

47.      Let .009/X = 0.1. Then, x = .009/.01 = .9/1 = .9.

48.      144/0.144 = 14.4/X 144 x 1000/144 = 14.4/X X = 14.4/1000 = 0.0144.

49.      Length of each piece = (1/8) m = 0.125 m.

Required number of pieces = (37.5/0.125) = (375 x 100 / 125) = 300.

50.  Suppose commodity X will cost 40 pairse more than Y after z years. Then,

(4.20 + 0.40 z) – (6.30 + 0.15 z) = 0.40.

0.25 z = 0.40 + 2.10 z = 2.50/0.25 = 250/25 = 10.

X will cost 40 pairse more than Y 10 years after 2001 i.e., in 2011.